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Thumper_10x7_CA: 10" / 77" x 100 = 13% (rounded up .01)

So what does that mean anyway? I'm a knumbskull when it comes to math.
 
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Phallostrates: [quote author=Thumper_10x7_CA link=board=meetgreet;num=1071355939;start=20#20 date=12/15/03 at 16:50:23]10" / 77" x 100 = 13% (rounded up .01)

So what does that mean anyway?  I'm a knumbskull when it comes to math.[/quote]

It's about proportion. Your dick length is 13% of the height of your body.
 
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wishIwashung: 6"/68" = 8.82% - how very sad. And to think I used to LIKE doing math.

Phooey :p
 
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mr18yearold: I am going to try and make a formula to incorporate girth as well...but this is difficult...so i will need some feedback...

L=Length (in inches)
G=Girth (in inches)
H=Height (in inches)

Before, the formula, (100xL)/H represents the % your cock is of your height. What this new formula is going to try and do is compair your cock size, both length and girth, to your height. The first obvious question is, should girth and length be considered equal numbers? We all know that the average girth is less than the average length. And can we also make the jump to say that girth is more important than length?... i think it has been discussed at nauseum else where in this site, and girth won... but correct me if im wrong. I am going to assume that Girth is twice as important as Length. Therefore, the new equation would be...
(100x((L+2G)/3)/H or simplified, (50x(L+2G))/H

In this equation, girth is counted twice, and the average (divide the sum of all number by how many numbers there are...2+1=3) of 2 times your girth and your length is taken, divided by your height, and multiplied by 100, to get a percentage of your penis size compared to that of your height.

However, this equation weighs length and girth equally, which they are not. If the average length is 6", and the average girth is 5", Length should be multiplied by 5/6 to make the length and girth numbers to equal.

Average length, 6".... 6x(5/6)=5
Average Girth, 5"... /

So therefore, the new equation is...

%=(100x((5/6)L + 2G))/H

Now i know what all you are saying, your weight should be included...but i just sat down and typed this up, so give me a break... i did the best i could... also, i would like to hear any comments you might have, or if any of my figures are wrong...or if you figure out how to add weight to the equation...peace out for now
 
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mr18yearold: wow... i cant believe i made such a mistake... lol... ill correct my two mistakes...

my first equation...

%=(100x(L+2G)/3)/H cannot be simplified... i was using 2 instead of 3 back when i simplified it...
for my second equation...

I made length smaller to make girth and length equal, but that was incorrect. I should have made girth bigger, by multiplying it by 6/5... so my new equation, all fixed is...

%=(100x(L+(12G/5))/3)/H

sorry for my ignorance, lol
 

Pecker

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[quote author=mr18yearold link=board=meetgreet;num=1071355939;start=20#34 date=12/19/03 at 18:14:22]is no one going to respond to my comments?[/quote]

Sure, mr18, your solid penis measurement makes little sense when compared to the planar height measurement. Kind of like comparing a beer can's measurements to a tablecloth.

But nice try.

Pecker

I found the ultimate Christmas tree. The day after Christmas it turns into a giant Easter Bunny.
 
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Ineligible: I think it's a mistake to try to compress two numbers that show some independence (i.e., the ratio between them varies) into one. Each could be quoted separately as a proportion of height, and that would give more information.

If you make a combined parameter, to be popular it needs to express something useful or interesting. Your parameter might be considered as "penis size as a percentage of height, notionally based on length but weighted 2/3 by girth". Not everyone might consider this an optimal parameter - or, at least, worth the calculation. People like simplicity!
 
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over13inches: Here I am with an A-Level in Maths and i'm still trying to get my head around %=(100x(L+(12G/5))/3)/H ??? ;D

However - first equation:

13.75"/74 = 18.58%

And the "%=(100x(L+(12G/5))/3)/H" equation:

(100x(13.75"+([12x8"]/5)/3)/74" = 14.84%

So my penis is 18.58 percent of my height, whilst 14.84% of my body height and width proportionally? Or am I just majorly confused now? ???