Jack Doherty

[smokeymountain1047]

Well I’ve seen it and it’s deffo him unless someone else wears the same bracelet

where have you seen it?

 

[Brandonjames31]

Jack posted a jerking vid

 

[sefgdeeeasdfg]

Jack posted a jerking vid

someone send it

 

[goreccg444]

Jack posted a jerking vid

where whats the vid called

 

[Theusrr]

where whats the vid called

It’s on his old account but it’s $99

 

[Zzzzsie8]

It’s on his old account but it’s $99

What you mean old account

 

[jdjendbjsm]

Omg really

 

[goreccg444]

i have all the vids locked on the old account but i dont see that one i would by it if it was there

 

[deleted2890891]

i have all the vids locked on the old account but i dont see that one i would by it if it was there

It was sent by message

 

[rufus491]

We would all love to see this if anyone is willing to pay the hundred dollars…

 

[Zzzzsie8]

i have all the vids locked on the old account but i dont see that one i would by it if it was there

I give this new account if you want

 

[Zzzzsie8]

i have all the vids locked on the old account but i dont see that one i would by it if it was there

Please buy on his new account I will the information buy it

 

[Lakesideway5]

View attachment 70144271

It’s a scam...

 

[Zzzzsie8]

It’s a scam...

How you know

 

[Zzzzsie8]

It’s a scam...

How you know that

 

[Zzzzsie8]

Buy it please

View attachment 70184741
Kinda better price dont know if it’s true tho

 

[thatoneguy90]

View attachment 70184741
Kinda better price dont know if it’s true tho

It doesn't say it's a jack off video but I bet the one where he claims that, might just be him doing it under his underwear. No offense to anyone, but I don't believe anyone claiming he's shown dick. Post it here if it's true. LOL

 

[Theusrr]

This one isn’t jerk it’s supposedly him getting fully naked

 

[jdjendbjsm]

This one isn’t jerk it’s supposedly him getting fully naked

Someone should buy it

 

[thatoneguy90]

Someone should buy it

Great, why don't you do it? I bet it's a scam.