mr18yearold: i guess i should be sorry...because yes, my equation is very complicated, and does not satisfy what it tries to accomplish. My goal was to relate penis size with how big a person was (i.e. their height and weight)...yet, as i am seeing from several people's comments, this is not easily done, and maybe is impossible...however, if anyone can come up with something more suitable to my goal, please feel free to post...i was just trying something new...obviously i failed
Ineligible: Hey, don't worry, mr18yearold. I like the way you are prepared to have a go. Far better to try and not succeed every time than never to try at all.
Don't change!
Don't change!
[quote author=mr18yearold link=board=meetgreet;num=1071355939;start=40#41 date=12/22/03 at 01:49:54]...i was just trying something new...obviously i failed[/quote]
No, mr18, you haven't failed. Thomas Edison would say that you've just discovered another way that doesn't work, that's all.
Pecker
I have a Liberal Arts Degree - do you want fries with that?
No, mr18, you haven't failed. Thomas Edison would say that you've just discovered another way that doesn't work, that's all.
Pecker
I have a Liberal Arts Degree - do you want fries with that?
nyc10x6: I am trying to figure out what this statistic is good for in the first place. A large percentage means you are a short guy with a big cock. An average percentage means you are a short guy with a small cock, a tall guy with a big cock, or an average guy with and average cock. I come in at 13.5%, which seems to be a typical response here. I guess that means that my cock length to body height ratio is average. The short hung guys win here. Even with a smaller cock, their short stature makes them appear more hung than they really are. (Actually I love short guys with big cocks!)
I am not sure what mr. 18 is trying to get at either. It might be interesting to compare volume of cock (or an approximation of it)...If you are not a math person, tune out here.
Approximating the volume of your cock to that of a cylinder (which of course, no one's cock is actually shaped like a perfect beer can), use the formula V=L pi r squared. In other words multiply the length of your cock by 3.14 and then multiply that figure by one-half the width (not circumference) of your cock sqaured.
My cock is 10" long and 2" wide at the thickest point. The volume is then 9.75x3.14x(1x1). Or 30.6 cubic inches. Of course since my cock isn't a pefect cylider the volume is quite a bit less, but if everyone uses the same method of calcuation, we can make reasonable comparisons.
Overkill, I know, but I am sure there are many curious people out there who want to see how they stack up. Anyone want to compare surface area? 2 × r × pi × L + 2 × pi × r squared.
I am not sure what mr. 18 is trying to get at either. It might be interesting to compare volume of cock (or an approximation of it)...If you are not a math person, tune out here.
Approximating the volume of your cock to that of a cylinder (which of course, no one's cock is actually shaped like a perfect beer can), use the formula V=L pi r squared. In other words multiply the length of your cock by 3.14 and then multiply that figure by one-half the width (not circumference) of your cock sqaured.
My cock is 10" long and 2" wide at the thickest point. The volume is then 9.75x3.14x(1x1). Or 30.6 cubic inches. Of course since my cock isn't a pefect cylider the volume is quite a bit less, but if everyone uses the same method of calcuation, we can make reasonable comparisons.
Overkill, I know, but I am sure there are many curious people out there who want to see how they stack up. Anyone want to compare surface area? 2 × r × pi × L + 2 × pi × r squared.
nyc10x6: sorry. in my above post i should have said my cock is 9.75 inches long and 2 inches wide, which are the figures I used for calcuation. not 10 inches.
Donk: [quote author=nyc10x6 link=board=meetgreet;num=1071355939;start=40#45 date=12/23/03 at 19:37:10] The short hung guys win here. [/quote]
And what's wrong with that!
And what's wrong with that!
- jonb,
[quote author=Poshman link=board=meetgreet;num=1071355939;start=0#0 date=12/13/03 at 14:43:18]What is the size of your penis compared to your height as a percentage. TO do this take the length of your penis in inches and divide by your height in inches. Times this by 100 and you've got your answer.
Cheers[/quote]
I myself am .136 (13.6%), but (just so wishiwashung doesn't feel bad) the average for humans is 12.3/175=.726 (Those are metric measures.)
I've been trying to work with a way to convert so that you have your actual penile weight without severing it. So far all I have is a metric way to do it. Imperial measures are harder to do because science was technically illegal during the Middle Ages (Just ask Galileo.), so it wasn't specially designed for these kinds of studies.
Cheers[/quote]
I myself am .136 (13.6%), but (just so wishiwashung doesn't feel bad) the average for humans is 12.3/175=.726 (Those are metric measures.)
I've been trying to work with a way to convert so that you have your actual penile weight without severing it. So far all I have is a metric way to do it. Imperial measures are harder to do because science was technically illegal during the Middle Ages (Just ask Galileo.), so it wasn't specially designed for these kinds of studies.
niner: [quote author=jonb link=board=meetgreet;num=1071355939;start=40#51 date=12/28/03 at 15:51:33]
...average for humans is 12.3/175=.726 (Those are metric measures.)...[/quote]
Maybe I'm missing something, but I consider myself to be fairly up there on my mathematical skills, and when I look at 12.3/175, it HAS to be less than 0.1. Do you mean .0726, possibly, as in 7.26%?
Personally, my ratios are 11.53% (linearly) and using this %=(100x(L+(12G/5))/3)/H formula that I have yet to fully grasp the logic behind, 10.51% Being 6.5 feet tall ruins it for me haha
...average for humans is 12.3/175=.726 (Those are metric measures.)...[/quote]
Maybe I'm missing something, but I consider myself to be fairly up there on my mathematical skills, and when I look at 12.3/175, it HAS to be less than 0.1. Do you mean .0726, possibly, as in 7.26%?
Personally, my ratios are 11.53% (linearly) and using this %=(100x(L+(12G/5))/3)/H formula that I have yet to fully grasp the logic behind, 10.51% Being 6.5 feet tall ruins it for me
haha[quote author=jonb link=board=meetgreet;num=1071355939;start=40#53 date=12/29/03 at 20:04:30]
Why the hell does everyone here use percentages for this?[/quote]
Maybe because that's what the original poster asked for. Look at the title of the thread: %!
Why the hell does everyone here use percentages for this?[/quote]
Maybe because that's what the original poster asked for. Look at the title of the thread: %!
